The area of rectangle is : 1595.62
Let the sides be x and y and divide the perimeter by 2
y = 32.3-x
Using Pythagoras: x^2+(32.3-x)^2 = 24.7^2
As a quadratic equation: 2x^2+433.2-64.6x = 0
Solving the equation: x = 9.5 or x = 22.8
Area: 9.5*22.8 = 216.6 square cm
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
The area of rectangle is : 13832.797999999999
The perimeter is 18 feet.
240 sq m
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
The area of rectangle is : 13832.797999999999
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
It works out as: 35 cm or 350 mm
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.