If the pool is 26 feet around, then its circumference is 26 feet. If the pool is 26 feet across, then its circumference is 81.7 feet.
6 pi ft
circumference = π x diameter => diameter = circumference ÷ π ~= 20ft ÷ 3.14 ~= 6.37 ft
If the question refers to a square, then circumference = 4d, where d is the length of a side. 20 = 4d therefore d = 20/4 = 5 ft. If the question refers to a circle with a circumference (C) of 20', then C = 2πr, where r is the radius of the circle. 20 = 2πr therefore r = 20 ÷ 2π = 3.18 ft If the question refers to the circumference of a circle with radius 20', then C = 2π x 20 = 40π = 125.66 ft
If the circle is 20 ft radius, the area is π·20² = 1256.637 ft² If the circle is 20 ft diameter, the area is π·(20/2)² = 314.1593 ft² If the circle is 20 ft circumference, the are is π·(20/2π)² = 63.66198 ft²
If the pool is 26 feet around, then its circumference is 26 feet. If the pool is 26 feet across, then its circumference is 81.7 feet.
If the diameter is 25 feet then the circumference is 78.5 feet (approx).
6 pi ft
That depends on what you mean by a "20 ft semicircle".A semi-circle is a half circle.A 20 ft circle could be:A circle of diameter 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2π 20 ft + 20 ft= 10π + 20 ft≈ 51.42 ftA circle of radius 20 ftThe perimeter of the semicircle is half the circumference plus double the radius → perimeter = 1/2 2π 20 ft + 2 x 20 ft= 20π + 40 ft≈ 102.08 ftA circle of circumference 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2 20 ft + 20 ft ÷ π= 10 ft + 20/π ft≈ 16.37 ftHowever, if a 20 ft circle is a circle with a circumference (= perimeter) of 20 ft then a 20 ft semi-circle could be a semicircle with a perimeter of 20 ft→ perimeter = 20 ft
circumference = π x diameter => diameter = circumference ÷ π ~= 20ft ÷ 3.14 ~= 6.37 ft
If the question refers to a square, then circumference = 4d, where d is the length of a side. 20 = 4d therefore d = 20/4 = 5 ft. If the question refers to a circle with a circumference (C) of 20', then C = 2πr, where r is the radius of the circle. 20 = 2πr therefore r = 20 ÷ 2π = 3.18 ft If the question refers to the circumference of a circle with radius 20', then C = 2π x 20 = 40π = 125.66 ft
Circumference of the circular pool: 20*pi feet
The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.
37 feet and 8.5 inches
484/7 = 69 and one seventh ft
If the circle is 20 ft radius, the area is π·20² = 1256.637 ft² If the circle is 20 ft diameter, the area is π·(20/2)² = 314.1593 ft² If the circle is 20 ft circumference, the are is π·(20/2π)² = 63.66198 ft²
That my friend would be 62.8