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8y ago

There can be many parabolas with the same vertex.

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8y ago

The equation is y = a(x^2/4 + ax + a) - 3 where a is any positive number.

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Q: A parabola has a vertex at -3 -2 what is its equation?
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The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5 What is the coefficient of the squared term in the parabola's equation?

The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.


What is the equation of a parabola with the vertex of 2 -1?

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The coordinates will be at the point of the turn the parabola which is its vertex.


The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?

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The vertex of this parabola is at (2, -4) When the y-value is -3, the x-value is -3 What is the coefficient of the squared term in the parabola's equation?

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What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?

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What is the coefficient of the squared term in the parabola's equation when the vertex is at -2 -3 and the point -1 -5 is on it?

A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (-2, -3), and a point on it is (-1, -5) → -5 = a(-1 - -2)² + -3 → -5 = a(1)² - 3 → -5 = a - 3 → a = -2 → The coefficient of the x² term is -2.


The vertex of this parabola is at (-2, -3) When the x-value is -1, the?

Y=a(x-h)+k is the vertex formula. Since the vertex is at (-2,-3) this parabola has the equation: y=a(x+2)^2-3 We can plug in x=-1 but we really need to know a, to solve for y. ( we can solve it, but we will have an a in the solution)


The vertex of this parabola is at 4 -3 Which of the equations below could be its equation?

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What is the equation of a parabola with vertex at 1 -3 and focus at 2 -3?

For a parabola with an axis of symmetry parallel to the x-axis, the equation of a parabola is given by: (y - k)² = 4p(x - h) Where the vertex is at (h, k), and the distance between the focus and the vertex is p (which can be calculated as p = x_focus - x_vertex). For the parabola with vertex (1, -3) and focus (2, -3) this gives: h = 1 k = -3 p = 2 - 1 = 1 → parabola is: (y - -3)² = 4×1(x - 1) → (y + 3)² = 4(x - 1) This can be expanded to: 4x = y² + 6y + 13 or x = (1/4)y² + (3/2)y + (13/4)


Find the vertex of the parabola y equals -2x2 plus 12x - 13?

The points at which the parabola intersects the x axis are 3-sqrt(10)/2 and 3+sqrt(10)/2. The X position of the vertex is in the middle, at 3. The y position, from there, is simply found by substituting 2 for x in the equation. As a result, the vertex is at (3, 5).


The vertex of this parabola is at 4 -3 When the x-value is 5 the y-value is -6 What is the coefficient of the squared expression in the parabola's equation?

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