answersLogoWhite

0


Best Answer

Equation of the circle: (x-7)^2 +(y-7)^2 = 49

User Avatar

Wiki User

6y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

6y ago

Equation of the circle: (x-7)^2+(y-7)^2 = 49

This answer is:
User Avatar

User Avatar

Wiki User

6y ago

It is (x - 7)2 + (y - 7)2 = 49.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the equation of the circle with a radius of 7 whose center is in the 1st quadrant and touches both the x and y axes?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?

Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49


What is the equation of the circle that touches the x axis when its center is at 2 5?

Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25


How do you write an equation for a circle with a center?

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2


What do you call a quadrant within a circle?

A quarter of a circle or a quadrant!


What do you call a line segment that passes through the center of a circle and touches two points on the circle?

The secant.


What is the equation of the circle with center 2 9 and radius 7?

depends on the equation.


What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?

9


If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?

The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.


What is the tangent line equation of the circle x2 plus y2 -8x -16y -209 equals 0 when it touches the circle at 21 8 on the Cartesian plane?

Equation of circle: x^2 +y^2 -8x -16y -209 = 0 Completing the squares: (x-4)^2 +(y-8)^2 = 289 Radius of circle: 17 Center of circle: (4, 8) Point of contact: (21, 8) Slope of radius: 0 Slope of tangent line: 0 Equation of tangent line: x = 21 which means it touches the circle at (21, 0) which is a straight vertical line parallel to the y axis


What is the equation for a circle with a center of (0 0) and a radius of 9?

The equation of the circle is: x^2 + y^2 = 81


How do you write an equation in standard form of a circle with a center and radius?

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2


What is the equation of a circle whose center is at the origin and whose radius is 10?

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100