x6 - 9 = (x3)2 - (3)2
And expansion for a2 - b2 is (a - b)(a + b)
Here a = x3 and b = 3
So, (x3)2 - (3)2 = (x3 - 3)(x3 + 3) = [x3 - (31/3)3][x3 + (31/3)3]
And the expansion for a3 - b3 is (a - b)(a2 + ab + b2)
And the expansion for a3 + b3 is (a + b)(a2 - ab + b2)
Here a =x and b = 31/3
So, [x3 - (31/3)3][x3 + (31/3)3] = {(x - 31/3)(x2 + 31/3x + x2)}{(x + 31/3)(x2 - 31/3x + x2)}
So factors are (x - 31/3), (x2 + 31/3x + x2), (x + 31/3) and (x2 - 31/3x + x2).
With great difficulty not knowing if 6x and 27 are plus or minus
(6x - 1)(6x - 1)
(2x - 3)(3x + 2)
(3x - 4)(2x^2 + 6x + 5)
6x(3x2 - x + 4)
x2 - 6x - 27 = (x-9)(x+3)
With great difficulty not knowing if 6x and 27 are plus or minus
6(x - 4)
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
3x(6x - 1)
(6x - 1)(6x - 1)
It is: (2x+3)(3x-8) when factored
x2-6x-27 = (x+3)(x-9) when factored
(2x - 3)(3x + 2)
The GCF is 3.
The factors are -1(2x + 1)(3x + 4)
(3x - 4)(2x^2 + 6x + 5)