0
What else can I help you with?
What is n over 18 x 6 over n to the 4th power?
(n/(18*6))/n4=(n/108)/n4 ;Multiply 18 and 6(n/108)*(1/n4) ;Multiply by the reciprocal of n4, which is just 1 over n4n/(n4*108) ;The n4 will go in the bottom of the fraction1/(108n3) ;n over n4 will give you 1 over n3
What is the four number where n has n digits?
4n or n4
What is the product of four and a number?
The product of four and a number would be algebraically written as 4n, or whatever variable equals the number. In this case, n = number. It would not be written n4, nx4, 4xn, 4*n or n*4, although n4 and the ones with stars may be accepted by a teacher.
Is there a relationship between the exponents of the base and the exponent of the product?
When multiplying numbers with the same base and different or same exponents, the product is the base to the power of the sum of the exponents of the multiplicands. Examples: 52 x 57 x 510 = 519 n x n4 = n5 75 ÷ 72 = 75 x 7-2 = 73 22 x √2 = 22 x 20.5 = 22.5
What is the formula for a proportion?
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
What is n over 18 x 6 over n to the 4th power?
(n/(18*6))/n4=(n/108)/n4 ;Multiply 18 and 6(n/108)*(1/n4) ;Multiply by the reciprocal of n4, which is just 1 over n4n/(n4*108) ;The n4 will go in the bottom of the fraction1/(108n3) ;n over n4 will give you 1 over n3
What is the four number where n has n digits?
4n or n4
C plus plus program calculate the power value of input base and exponent numbers?
cn = c0 *( 1 + i ) pow n
How do you find the base and exponent of a number?
in a problem like n4=625 you need to do a mult-step equations In the example, 4log n = log 625 log n = (log 625)/4 n = 10^[(log 625)/4] = 5 Although this particular answer is obvious, you could also solve n5=625, or any other power of n, which isn't, using this method. hope that it is helpful to you!
What is the product of four and a number?
The product of four and a number would be algebraically written as 4n, or whatever variable equals the number. In this case, n = number. It would not be written n4, nx4, 4xn, 4*n or n*4, although n4 and the ones with stars may be accepted by a teacher.
Is there a relationship between the exponents of the base and the exponent of the product?
When multiplying numbers with the same base and different or same exponents, the product is the base to the power of the sum of the exponents of the multiplicands. Examples: 52 x 57 x 510 = 519 n x n4 = n5 75 ÷ 72 = 75 x 7-2 = 73 22 x √2 = 22 x 20.5 = 22.5
Can the base of a logarithm be 0?
No, it is undefined and indeterminate. Log base y of a variable x = N y to the N power = x if y ( base) = 0 then 0 to the N power = x which is always zero (or one in some cases) and ambiguous. Say you want log base 0 of 50 0 to the N power = 50 cannot be true as 0 to the N is always zero
What is the value of 2 to the power of n?
Just write it as 2 to the power n. You can't simplify that, and you can only calculate a specific value if you know the value of n.
When a n number is raised to a power the number that is used as a factor is?
the number is the BASE and the power is the EXPONENT. your question is not clearly formulated
What is the formula for a proportion?
1.What is the formula for a proportionp = n / f2. p = (f / 100) * n3. p = f / n4. p = (f / n) * 100
What are the factors of n to the twelfth?
The factors of n12 are 1, n, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, and n12
The product of four consective integers is one less than a perfect square?
Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.
