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What is the formula to work out how many times can you rearrange the letters in the word chocolate?
Wiki User
∙ 10y ago
The answer to the question that is asked is that there is no limit other than your life span. There is no requirement from the question that the arrangements should be different.
But, if you want the number of distinct arrangements, the formula is derived as follows:
There are 9 letters in chocolate so that gives a preliminary answer of 9! ways.
But the letters c and o appear twice. The two cs can be swapped in 2! ways, and the two os in anothr 2! way without changing the arrangement. So the final answer is
9!/(2!*2!) = 362,880/(2*2) = 90,720 ways.
The answer to the question that is asked is that there is no limit other than your life span. There is no requirement from the question that the arrangements should be different.
But, if you want the number of distinct arrangements, the formula is derived as follows:
There are 9 letters in chocolate so that gives a preliminary answer of 9! ways.
But the letters c and o appear twice. The two cs can be swapped in 2! ways, and the two os in anothr 2! way without changing the arrangement. So the final answer is
9!/(2!*2!) = 362,880/(2*2) = 90,720 ways.
The answer to the question that is asked is that there is no limit other than your life span. There is no requirement from the question that the arrangements should be different.
But, if you want the number of distinct arrangements, the formula is derived as follows:
There are 9 letters in chocolate so that gives a preliminary answer of 9! ways.
But the letters c and o appear twice. The two cs can be swapped in 2! ways, and the two os in anothr 2! way without changing the arrangement. So the final answer is
9!/(2!*2!) = 362,880/(2*2) = 90,720 ways.
The answer to the question that is asked is that there is no limit other than your life span. There is no requirement from the question that the arrangements should be different.
But, if you want the number of distinct arrangements, the formula is derived as follows:
There are 9 letters in chocolate so that gives a preliminary answer of 9! ways.
But the letters c and o appear twice. The two cs can be swapped in 2! ways, and the two os in anothr 2! way without changing the arrangement. So the final answer is
9!/(2!*2!) = 362,880/(2*2) = 90,720 ways.
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoThe answer to the question that is asked is that there is no limit other than your life span. There is no requirement from the question that the arrangements should be different.
But, if you want the number of distinct arrangements, the formula is derived as follows:
There are 9 letters in chocolate so that gives a preliminary answer of 9! ways.
But the letters c and o appear twice. The two cs can be swapped in 2! ways, and the two os in anothr 2! way without changing the arrangement. So the final answer is
9!/(2!*2!) = 362,880/(2*2) = 90,720 ways.
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