Since 50abc is a factor of 50ab2c3, it is automatically the GCF.
Your question makes no sense and therefore unanswerable.
b
The GCF is 27b.
ab=50 a/b=2 a=2b 2b2=50 b2=25 b=5 5a=50 a=10 (10,5)
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
as a2+b2=(a+ib)(a-ib), b2+2=[b - i sqrt(2)] [b + i sqrt(2)]
Answer: GCF= b
The GCF is a2b.
b
34 + b2 + (-c)3 = 81 + b2 + -c3
34 + b2 + c3
The GCF is 27b.
(a+b)2a2+b2+2ab(a-b)2=a2+b2-2ab(a+b)2=(a-b)2+4ab(a-b)2=(a+b)2-4aba2-b2=(a+b)(a-b)(a+b+c)2=(a+b+c+2ab+2bc+2cz)(a+b)3=a3+b3+3ab(a+b)(a-b)3=a3-b3-3ab(a-b)a3+b3=(a-b)(a2-ab+b2)a3-b3=(a+b)(a2+ab+b2)a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)(x+a)(x+b)=x2+x(a+b)+ab ==3a+10b-b+2a=5a+9by=mx+b is another one
The simplest way is as follows: =B2+C3
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
ab=50 a/b=2 a=2b 2b2=50 b2=25 b=5 5a=50 a=10 (10,5)
10b
a2-b2 = (a-b)(a+b)