I assume you mean the last digit. The idea is to find a pattern:
8 to the power 1 ends with 8
8 to the power 2 ends with 4
8 to the power 3 ends with 2 (to figure this out, I just multiplied 4 x 8)
8 to the power 4 ends with 6 (once again, multiply the last digit of the previous power x 8)
8 to the power 5 ends with 8
8 to the power 6 ends with 4
...
As you can see, it all repeats, with a period of 4. Therefore, any exponent that is a multiple of 4 will end with 6. Find the nearest multiple of 4 that is smaller than 2015, then continue calculating - always with the last digit.
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if the last number is 0,2,4,6 or 8
It is 8 because any number to the power of zero is 1
Numbers are divisible by 8 if the number formed by the last three individual digits is evenly divisible by 8. For example, the last three digits of the number 3624 is 624, which is evenly divisible by 8 so 3624 is evenly divisible by 8.
No because 2 to the power of 3 is 8 which is a rational number
Multiply by 8 just like any other number. For example 3 x 8 = 24. To determine if a number is divisible by 8, just consider the last three digits. For example: 25654789008 is divisible by 8 because the last three digits (008) are divisible by 8 (008 / 8 = 1). 78945987345007 is not divisible by 8 because the last three digits are not divisible by 8 (007 / 8 = 0.875).