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I assume you mean the last digit. The idea is to find a pattern:

8 to the power 1 ends with 8

8 to the power 2 ends with 4

8 to the power 3 ends with 2 (to figure this out, I just multiplied 4 x 8)

8 to the power 4 ends with 6 (once again, multiply the last digit of the previous power x 8)

8 to the power 5 ends with 8

8 to the power 6 ends with 4

...

As you can see, it all repeats, with a period of 4. Therefore, any exponent that is a multiple of 4 will end with 6. Find the nearest multiple of 4 that is smaller than 2015, then continue calculating - always with the last digit.

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10y ago

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