What number would you like to be next?
Using U{n} = (5.25n⁴ - 58n³ + 249.75n² - 554n + 621)/3
it gives {88, 44, 22, 11} for n = 1, 2, 3, 4, so the next term is U{5} = 42.
However, the solution I suspect your teacher wants is that it is a GP with each term half the previous term (ie a common ratio of ½) so the next term is 11×½ = 11÷2 = 5½ = 5.5
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.
For example, using the simplest polynomial rule
T(n) = (-11n3 + 132n2 - 583n + 990)/6 gives the next term as 0, while another,
T(n) = (9n4 - 112n3 + 579n2 - 1616n + 2196)/12 gives the next term as 18.
66
44 2 22 2 11
1&44 2&22 4&11
No, since 11 is less than 44 it can not be a multiple, as it is defined (basically) as a number achievable by multiplying the base number by some integer. e.x.: 22 is a multiple of 11 ( 11 x 2 = 22 ). 44 is a multiple of 11 ( 11 x 4 = 44 ). 11 is not a multiple of 44 ( 44 x 1/4 = 11) since 1/4 is not an integer.
11
66
1, 2, 4, 11, 22, 44.
44 2 22 2 11
1&44 2&22 4&11
1, 2, 4, 11, 22, 44
11 = 1 22 = 4 33 = 27 44 = 256 55 = 3125
1, 2, 11, 22.
No, since 11 is less than 44 it can not be a multiple, as it is defined (basically) as a number achievable by multiplying the base number by some integer. e.x.: 22 is a multiple of 11 ( 11 x 2 = 22 ). 44 is a multiple of 11 ( 11 x 4 = 44 ). 11 is not a multiple of 44 ( 44 x 1/4 = 11) since 1/4 is not an integer.
The factors of 44 are: 1, 2, 4, 11, 22, and 44 . 1, 2, 4, 11, 22, 441,2,4,11,22,441 times 44 44 times 12 times 22 22 times 24 times 11 or 11 times 41, 2, 4, 11, 22, 44
The factors of 22 are 1, 2, 11, and 22. The factors of 44 are 1, 2, 4, 11, 22, and 44.
11
11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121