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First of all, an area of 100 feet is not possible since area is measured in square feet - not in feet. But suppose we overlook that fundamental error.
The area of a rectangle is not sufficient to determine its perimeter. It can have any value greater than 40 ft.
Let L be ANY length ≥ 10 ft and let W = 100/L ft.
Then, a rectangle with length L and width W has an area of L*W = L*100/L = 100 square feet. But since there are infinitely many choices for L, there are infinitely many perimeters (P).
For example,
L = 10 => W = 10 => P = 40
L = 100 => W = 1 => P = 202
L = 1000=> W = 0.1 => P = 2000.2
L = 10000=> W = 0.01 => P = 20000.02
You should see from that, there is no limit to how large L can be and so no limit on how large P can be.
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The perimeter of a rectangle is 18 ft and the area of the rectangle is 14 square ft what is the width of the rectangle?
2 ft
What is the perimeter of a rectangle floor with area of 100 sq ft and length of 10 ft?
Width = Area/Length = 100/10 = 10 feet. Perimeter = 2*(L + W) = 2*(10 + 10)= 40 feet.
What is the perimeter if the area is 2549 sf?
The area is not sufficient information to determine the perimeter. First of all, there is no reason to suppose that the area is rectangular as opposed to circular or triangular or some other simple or complicated shape. So, all that can be said is that the perimeter is greater than 178.97 feet, a perimeter that is attained when the area is a circle. If the area is a rectangle, it could be 25.49 ft * 100 ft so that the perimeter is approx 250.98 ft or 2.549 ft * 1000 ft and a perimeter of 2005.10 ft or 0.2549 ft * 10000 ft and a perimeter of 2000.51 ft or 0.0002549 ft * 10000000 ft and a perimeter of 2000000 ft. By making the rectangle thinner and longer, the perimeter can be increased without limit.
What is the perimeter and area of rectangle with a length of 0.6 ft and a width of 2.4 ft?
Area is 1.44 square feet Perimeter is 6 feet.
What has an area of 36 sq ft and a perimeter of 26 ft?
A 4 ft by 9 ft rectangle
