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With a standard 6 faced die, numbered 1 through 6, there are three odd numbers, 1, 3, and 5, of which 3 and 5 are prime, and there is one even prime, 2. The probability, then, of rolling an odd number which is prime is 1 in 3, i.e. 3 or 5 out of a possible result set of 1, 2, 3, 4, 5, and 6.
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What is the probability of rolling an even number or a prime number on a cube.write as a fraction in simplest form?
Even probability: 3/6= 1/2 Odd probability: 3/6= 1/2 (a cube has six sides and normally is numbered 1-6)
What is the probability of rolling an odd prime number with one toss of a dot cube?
Odd prime numbers from 1-6 are 2, 3, and 5. Since there are three numbers, it would be three out of six, or 3/6 which can be simplified to 1/2 aka 50%.
What is the probability of choosing neither an odd number nor prime number from 1 to 50?
24/50
When rolling 2 number cubes the Podds and odds is?
If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.
What is the least odd prime number?
3 is the smallest odd prime number.
