0
50% chance
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
1/6 x 1/6 x 1/6 = 1/216
(1/6)^3 since each event is independent and each has a probability of 1/6.
50% chance
The probability of rolling a six is one in six. The probability of rolling three consecutive sixes is one in 216. (1/6 x 1/6 x 1/6 = 1/216)
The probability is 1 and you do not need Matlab to get that answer - only a little bit of thought.
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
2/12 or 1/6
It is (1/6)5 = 1/7776 = 0.00013 approx.