Probability = number_of_ways_of_success/total_number_of_ways
If two events are independent, their probabilities are multiplied together, eg tossing a coin to get heads and throwing a 6 with a single [standard cube] die.
In this case, I guess you are choosing 4 marbles at random. This is the same as choosing one marble, then choosing the next WITHOUT replacing the first marble; each random choice of marble is independent of the previous in so far as the colour only depends upon what is left in the bag.
So the probability here is the product of the probability that the first marble is red, the next marble (without the first being replaced) is red and so on until 4 have been chosen:
Pr(1st red) = 5/15 (= 1/3) as there are 5 red marbles and 5+10=15 marbles in the bag
Pr(2nd red) = 4/14 (= 2/7) as there are now only 4 red and 4+10 = 14 marbles in the bag
Pr(3rd red) = 3/13 as there are now only 3 red marbles and 3+10 = 13 marbles in the bag
Pr(4th red) = 2/12 (= 1/6) as there are now 2 red marbles and 2+10 = 12 marbles in the bag.
Thus Pr(4 red) = Pr(1st red) × Pr(2nd red) × Pr(3rd red) × Pr(4th red)
→ Pr(4 red) = 1/3 × 2/7 × 3/13 × 1/6 = 1/273 ≈ 0.00366 ≈ 0.366 %
Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32
It is 1/6 for a single roll.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
25%
Cox Proportional is the most suitable hazard analysis for showing probability in Hazards Modeling.
Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32
It is 1/6 for a single roll.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
A number cube has six faces, so the probability of any one of them showing on a fair throw is 1 in 6, or about 0.1667.
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
The formula that is a diagram showing the bonding between atoms is called the structural formula. An example of structural formula would be for acetone OC(CH3)2.
That's one face out of six. So the probability is 1/6
Just hide the Formula Bar.
25%
It is 3/36 = 1/12