3
7 and 3
60000000 = 6*10^7
10 and 7
To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).
10 and 3
7x + 10
the sum of 10 and the product of 7 and a number 2+5=7 2*5=10
The difference of 7 and the product of 30 is calculated by subtracting the product of 30 from 7. The product of 30 is 30 multiplied by 7, which equals 210. Therefore, the difference of 7 and the product of 30 is -203.
3
70
7x - 10
10
7 and 3
42
60000000 = 6*10^7
The product of 3 and 7 is found by multiplying the two numbers together, which equals 21. The sum of 3 and 7 is found by adding the two numbers together, which equals 10. Therefore, the difference between the product of 3 and 7 and the sum of 3 and 7 is 21 - 10 = 11.
31