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Is x equals 1 a solution of the equation 2 - 8x?
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
What is the tangent equation of the circle 2x squared plus 2y squared -8x -5y -1 that touches the point of 1 -1 on the Cartesian plane?
If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0
What is the perpendicular bisector equation that meets the line segment of -1 3 and -2 -5?
Midpoint: (-3/2, -1) Gradient or slope: 8 Perpendicular slope: -1/8 Equation: y- -1 = -1/8(x- -3/2) y = -1/8x -3/16 -1 y = -1/8x -19/16 The perpendicular equation can be expressed in the form of: 2x+16y+19 = 0
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
Is x equals 1 a solution of the equation 2 - 8x?
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
What is the tangent equation of the circle 2x squared plus 2y squared -8x -5y -1 that touches the point of 1 -1 on the Cartesian plane?
If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0
What is the tangent equation at the point of 1 -1 when it touches the circle of 2x2 plus 2y2 -8x -5y -1 equals 0?
The tangent equation that touches the circle 2x^2 +2y^2 -8x -5y -1 = 0 at the point of (1, -1) works out in its general form as: 4x +9y +5 = 0
What is the perpendicular bisector equation that meets the line segment of -1 3 and -2 -5?
Midpoint: (-3/2, -1) Gradient or slope: 8 Perpendicular slope: -1/8 Equation: y- -1 = -1/8(x- -3/2) y = -1/8x -3/16 -1 y = -1/8x -19/16 The perpendicular equation can be expressed in the form of: 2x+16y+19 = 0
Is x equals 1 a solution of the equation 2 - 8x equals 6?
No.
What is 2 divided by 8x as a fraction in the simplest form?
0.25
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
Solve this equation using addition method -8x plus 3y equals -5 and 8x subtract 2y equals 6?
x=1, y=1
7 plus 8x-5 equals 8x plus 7-5x?
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
What is the solution to x-8x equals 1?
x - 8x = 1 Perform the indicated subtraction on the left side: -7x = 1 Divide each side of the equation by -7 : x = - 1/7
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
