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What is the slope-intercept form of the equation 8x y -1?

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∙ 11y ago

Updated: 12/10/2022

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Without an equality sign it is not an equation and the - or+ values of y are not given.

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∙ 11y ago

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Q: What is the slope-intercept form of the equation 8x y -1?

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Is x equals 1 a solution of the equation 2 - 8x?

No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.

What is the tangent equation of the circle 2x squared plus 2y squared -8x -5y -1 that touches the point of 1 -1 on the Cartesian plane?

If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0

What is the perpendicular bisector equation that meets the line segment of -1 3 and -2 -5?

Midpoint: (-3/2, -1) Gradient or slope: 8 Perpendicular slope: -1/8 Equation: y- -1 = -1/8(x- -3/2) y = -1/8x -3/16 -1 y = -1/8x -19/16 The perpendicular equation can be expressed in the form of: 2x+16y+19 = 0

What are the solutions for the quadratic equation 8x x2 - 9?

If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9

Solve this equation using addition method -8x plus 3y equals -5 and 8x subtract 2y equals 6?

x=1, y=1

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Related Questions

Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?

y = 2x + 1.

Is x equals 1 a solution of the equation 2 - 8x?

No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.

What is the tangent equation of the circle 2x squared plus 2y squared -8x -5y -1 that touches the point of 1 -1 on the Cartesian plane?

If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0

What is the tangent equation at the point of 1 -1 when it touches the circle of 2x2 plus 2y2 -8x -5y -1 equals 0?

The tangent equation that touches the circle 2x^2 +2y^2 -8x -5y -1 = 0 at the point of (1, -1) works out in its general form as: 4x +9y +5 = 0

What is the perpendicular bisector equation that meets the line segment of -1 3 and -2 -5?

Midpoint: (-3/2, -1) Gradient or slope: 8 Perpendicular slope: -1/8 Equation: y- -1 = -1/8(x- -3/2) y = -1/8x -3/16 -1 y = -1/8x -19/16 The perpendicular equation can be expressed in the form of: 2x+16y+19 = 0

Is x equals 1 a solution of the equation 2 - 8x equals 6?

No.

What is 2 divided by 8x as a fraction in the simplest form?

0.25

What are the solutions for the quadratic equation 8x x2 - 9?

If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9

Solve this equation using addition method -8x plus 3y equals -5 and 8x subtract 2y equals 6?

x=1, y=1

7 plus 8x-5 equals 8x plus 7-5x?

7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1

What is the solution to x-8x equals 1?

x - 8x = 1 Perform the indicated subtraction on the left side: -7x = 1 Divide each side of the equation by -7 : x = - 1/7

The line given by the equation y equals -8x is perpendicular to what line?

It would be perpendicular to a line with the equation Y = 1/8 X.

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