-14
first write in standard from as
y = mx + b where m = slope of line
2x - y = 16
2x = 16 + y
y = 2x -16
therefore m =2
a parallel line has the same slope
thus m = slope = 2
2xy=2*30*2=120
15xy-2xy-7x+x=13xy-6x
No, it equals -2xy. lrn2math
Y=15/(2c+2x)
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
2xy=2*30*2=120
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
15xy-2xy-7x+x=13xy-6x
No, it equals -2xy. lrn2math
First, all of these numbers are even, so halving everything would be a nice place to start:2x-y=1Then, rearrange to get y on one side of the equation:2x-y=1-y=1-2xy=-(1-2x)y=2x-1Finally, check the coefficient of x (number being multiplied by x):y=2x-1Therefore the slope of this line is 2.
It's an hyperbola equation.
Because 2x+y is addition not multiplication
Y=15/(2c+2x)
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
2xy
2xy*9 if x=3 and y = 2 2(3)(2)*9 12*9 108 You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.
(2xy)x=2x2y