2xy*9 if x=3 and y = 2
2(3)(2)*9
12*9
108
You substitute x and y for their equivalent (3 and 2) then simply multiply 2*x*y, then multiply the answer of that by 9.
Evaluate 2xy + 9 if x = 3 and y = 2.
2xy=2*30*2=120
2xy
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
The question doesn't nail it down; i.e., there can be several answers that satisfy the given information. Perimeter 'P' = 2 x (Length + Width) Area 'A' = (Length) x (Width) = 2 x y What is the Length, and what is the Width ? Here are five correct answers: ==> If the rectangle is (2) by (x y), A = 2xy, P = 4 + 2xy ==> If the rectangle is (2x) by (y), A = 2xy, P = 4x + 2y ==> If the rectangle is (x) by (2y), A = 2xy, P = 2x + 4y ==> If the rectangle is (1) by (2xy), A = 2xy, P = 2 + 4xy ==> If the rectangle is (0.1) by (20xy), A = 2xy, P = 0.2 + 40xy
x = -2
2xy=2*30*2=120
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
2xy
yes * * * * * No, it isn't. 2xy = 2 times x times y. Depending on which you mean: 2x2y = 2 times x times 2 times y = 4xy; OR 2x2y = 2 times x times x times y.
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.
The question doesn't nail it down; i.e., there can be several answers that satisfy the given information. Perimeter 'P' = 2 x (Length + Width) Area 'A' = (Length) x (Width) = 2 x y What is the Length, and what is the Width ? Here are five correct answers: ==> If the rectangle is (2) by (x y), A = 2xy, P = 4 + 2xy ==> If the rectangle is (2x) by (y), A = 2xy, P = 4x + 2y ==> If the rectangle is (x) by (2y), A = 2xy, P = 2x + 4y ==> If the rectangle is (1) by (2xy), A = 2xy, P = 2 + 4xy ==> If the rectangle is (0.1) by (20xy), A = 2xy, P = 0.2 + 40xy
6
x = -2
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-11
2xy x is 2 y is 7 therefore (2)(2)(7) = 28
to evaluate 5 squared you must simply do 5x5. Which equals 25.