4
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
1
Slope=3, y-intercept=0. y=3x or y=3x+0
9
Need slope intercept form. Y = mX + c 3X - Y = 6 - Y = - 3X + 6 Y = 3X - 6 =========== slope(m) = 3 ------------------
-3
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
1
Slope=3, y-intercept=0. y=3x or y=3x+0
The slope of y is -3x, hope that help
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
As long as there are no exponents and your slope (ie 3) is a constant number, then it is parallel if the y-intercept is different.
9
y = mx + b y-5 = 3x-1 y-5+5 = 3x-1+5 y = 3x + 4
Need slope intercept form. Y = mX + c 3X - Y = 6 - Y = - 3X + 6 Y = 3X - 6 =========== slope(m) = 3 ------------------
y-intercept is 10 slope is 3 over 1
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept