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Pick a and b as the last two digits (and we may assume a is greater than b). Make the remaining first seven digits the same as each other (any way will be fine). The last two digits will be ab for the first number and ba for the second number. The value of ab is 10a+b, the value of ba is 10b+a. The difference is (10a+b)-(10b+a)= 9a-9b = 9(a-b). To minimise this we just make a and b consecutive integers - there are eight ways of doing this. There are 7! ways of arranging the first seven digits. So 8! ways of choosing the numbers.

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Tom 1107

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The sum of 3 consecutive odd integers is less than 150. What are the largest possible values for the integers?

The largest possible values for the integers are 47, 49, and 51.


What is the greatest possible common divisor of two different positive integers which are less than 144?

71.(142/2).


9 squared belongs to what family of real numbers?

At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.


What three numbers with mean of 5 and range of 7?

If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.


What is the smallest possible value of 20P plus 10Q plus R when P and Q and R are different positive integers?

To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.

Related Questions

The sum of five different positive integers is 500 The largest possible value for one of these integers is?

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The sum of 3 consecutive odd integers is less than 150. What are the largest possible values for the integers?

The largest possible values for the integers are 47, 49, and 51.


What includes positive whole numbers their opposites and zero?

The set of all real numbers is one possible answer.


What is the greatest possible common divisor of two different positive integers which are less than 144?

71.(142/2).


9 squared belongs to what family of real numbers?

At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.


What three numbers with mean of 5 and range of 7?

If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.


What is the smallest possible value of 20P plus 10Q plus R when P and Q and R are different positive integers?

To find the smallest possible value of 20P + 10Q + R when P, Q, and R are different positive integers, we should start by assigning the smallest possible values to P, Q, and R. Since they are different positive integers, we can assign P = 1, Q = 2, and R = 3. Substituting these values into the expression, we get 20(1) + 10(2) + 3 = 20 + 20 + 3 = 43. Therefore, the smallest possible value of 20P + 10Q + R is 43.


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It is not possible to tell if the difference give an organism an advantage because you have not given the difference.


Is collection of negative integers a set?

yes and it is possible to do


2 positive integers whose product is 24999999 whose positive difference is as small as possible?

well, the square root of 24999999 is 4999.999, and the answer is 4999 • 5001. Hope this helps!