0
There are an infinite number of values that can be given for x and y to fit this equation. If you're looking to find out where it intercepts the x-axis, you can do so by solving for y = 0:
x2 - x - 12 = 0
(x - 4)(x + 3) = 0
x ∈ {-3, 4}
If you want to solve for when it intercepts the y-axis, then let x = 0:
y = 02 - 0 - 12
y = -12
If you want to find it's vertex, then you can do this a couple of ways. One would be to find it's derivative and solve for 0:
dy/dx = 2x - 1
0 = 2x - 1
2x = 1
x = 0.5
Now plug that back into the original equation to get the y co-ordinate:
y = 2(0.5) - 0.5 - 12
y = 1 - 0.5 - 12
y = -11.5
So the vertex is at the point (0.5, 11.5).
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How many solutions does 2x-y equals 8 and x plus y equals 1 have?
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Infinitely many: they are the same line!
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1
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Two solutions and they are:- x = 0 and y = 3
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How many solutions does 2x-y equals 8 and x plus y equals 1 have?
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How many solutions does x equals y and y equals x have?
Infinitely many: they are the same line!
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1
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It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
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Two solutions and they are:- x = 0 and y = 3
What are the solutions to the simultaneous equations of x squared plus y squared equals 20 and 2y minus x equals 0?
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1
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0
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[x + y = 6] has an infinite number of solutions.
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It works out that the solutions are: x = 3 and y = 2
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There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions. One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0
