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There are an infinite number of values that can be given for x and y to fit this equation. If you're looking to find out where it intercepts the x-axis, you can do so by solving for y = 0:

x2 - x - 12 = 0

(x - 4)(x + 3) = 0

x ∈ {-3, 4}

If you want to solve for when it intercepts the y-axis, then let x = 0:

y = 02 - 0 - 12

y = -12

If you want to find it's vertex, then you can do this a couple of ways. One would be to find it's derivative and solve for 0:

dy/dx = 2x - 1

0 = 2x - 1

2x = 1

x = 0.5

Now plug that back into the original equation to get the y co-ordinate:

y = 2(0.5) - 0.5 - 12

y = 1 - 0.5 - 12

y = -11.5

So the vertex is at the point (0.5, 11.5).

Q: What is the solutions to y equals x2-x-12?

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2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2

Infinitely many: they are the same line!

1

Two solutions and they are:- x = 0 and y = 3

0

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2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2

Infinitely many: they are the same line!

The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.

1

It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations

Two solutions and they are:- x = 0 and y = 3

0

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The solutions are: x = 4, y = 2 and x = -4, y = -2

[x + y = 6] has an infinite number of solutions.

It works out that the solutions are: x = 3 and y = 2

There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions. One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0