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Aglae Pacocha
Wiki User
∙ 11y agoThere are an infinite number of values that can be given for x and y to fit this equation. If you're looking to find out where it intercepts the x-axis, you can do so by solving for y = 0:
x2 - x - 12 = 0
(x - 4)(x + 3) = 0
x ∈ {-3, 4}
If you want to solve for when it intercepts the y-axis, then let x = 0:
y = 02 - 0 - 12
y = -12
If you want to find it's vertex, then you can do this a couple of ways. One would be to find it's derivative and solve for 0:
dy/dx = 2x - 1
0 = 2x - 1
2x = 1
x = 0.5
Now plug that back into the original equation to get the y co-ordinate:
y = 2(0.5) - 0.5 - 12
y = 1 - 0.5 - 12
y = -11.5
So the vertex is at the point (0.5, 11.5).
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