y2
Y²-5Y+4=0 Y1=-(-5/2) - Square root of ((-5/2)²-4) Y1= 2.5 - Square root of 2.25 Y1 = 1 Y2=-(-5/2) + Square root of ((-5/2)²-4) Y2= 2.5 + Square root of 2.25 Y2 = 4 Y can be either 1 or 4
If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).
y2 - 15 = 10Add 15 to each side:y2 = 25Take the square root of each side:y = +5y = -5
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
y2
Y²-5Y+4=0 Y1=-(-5/2) - Square root of ((-5/2)²-4) Y1= 2.5 - Square root of 2.25 Y1 = 1 Y2=-(-5/2) + Square root of ((-5/2)²-4) Y2= 2.5 + Square root of 2.25 Y2 = 4 Y can be either 1 or 4
y2 = 169 Square root both sides: y = 13
Let A1 be the area of the first square and X the length of its side Let A2 be the area of the second square and Y the length of its side A1 = X2 , A2 = Y2 , A1/A2 = X2/Y2 , Square Root (A1/A2) = Square Root ( X2/Y2), X/Y = Square Root (A1/A2) = Square Root (2/1) = 1.414
If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).
sqrt(36) * y2 = 6*y2
Do the multiplication, then take the square root. After the multiplication, you get 28x4y2. The square root of 28 is 2 times the root of 7, the square root of x4 is x2, and the root of y2 is y. So, the final result is 2 times square root of 7, times x2y.
Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58
y2 - 15 = 10Add 15 to each side:y2 = 25Take the square root of each side:y = +5y = -5
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
midpoint: (x1+x2/2 , y1+y2/2) quadratic: -b plus or minus square root b squared minus 4ac divided by 2a
X2= Y2+Z2 X is the hypotenuse as it is the longest side. Y and Z can be either of the sides. Example: X2=22+42 X2=4+16 X2=20 SQUARE ROOT 20 X= 4.47 X= 4.5 OR 62= Y2+42 36=Y2+16 36-16=Y2 Y2=20 SQUARE ROOT 20 Y=4.47 Y=4.5