y2=x3+3x2
y=±√15
Divide both sides of the equation by Y2.That will leave you with X / Y2 = Y* * * * *That doesn't quite do it, does it? Try this:Take the cube root of both sides.y = ³√x.
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
-0.82 , -4.82
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
x2 + y2 = 2r2
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
y2=x3+3x2
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
y=5xx2+y2=26Substitute the first equation into the second for y.x2 + (5x)2 = 26x2 + 25x2 = 2626x2 = 26x2 = 1x = SQRT(1) = 1 & -1y = 5*1 = 5y = 5*-1 = -5So the solutions are: (1,5) & (-1, -5)
Without an equality sign the given expression can't be considered to be an equation but if it equals to 0 then its solutions would be y = 2 or y = -5 which is not a perfect square
y2 there will me many solutions
9
y=±√15
7