Study guides

☆☆

Q: What is the sum of the first 4 multiples of 5?

Write your answer...

Submit

Still have questions?

Related questions

75

30

90

50 By plus i assume you mean sum. The first four multiples of 5 are 5,10,15, and 20 5+10+15+20=50

25,20,5,30

The first 3 multiples of 4 are: 4, 8, and 12.The first 3 multiples of 5 are: 5, 10, and 15.

The first 5 multiples of 4 are 4, 8, 12, 16, then 20.

The first 5 multiples of 1 are: 1, 2, 3, 4, and 5.

The first 3 common multiples of 4 and 5 are: 20, 40, and 60.

The first 5 multiples of 4 and 20 are 20, 40, 60, 80, 100

The first 5 multiples of 1 are: 1, 2, 3, 4, and 5.

+/- 2 and +/- 5

5, 10, 15, 20

5, 15, 25, 35

write the first three common. multiples of 3,4,5

0, 2, 4, 6, 8.0,2,4,6,8 are the first five multiples of 2

5 + 10 + 15 + 20 + 25 + 30 + 35 = 140 ANSWER = 140

4,8,12,16,20

They are: 20, 40.

The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.

The sum of the first 5 numbers is 15. 1+2+3+4+5=15

.....5 .....Σ 9r ...r=1

5, 10, 15, 20

1, 2, 3, 4, 5.

1, 2, 3, 4, 5.

People also asked