90
975
10+20+30 = 60
It is: 6+12+18 = 36
The first 5 multiples of seventeen are 17,34,51,68, and 85.
90
5 + 10+15+20=50 ans
The sum of the first 10 multiples of 3 is 165.
50 By plus i assume you mean sum. The first four multiples of 5 are 5,10,15, and 20 5+10+15+20=50
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
5 + 10 + 15 + 20 + 25 + 30 + 35 = 140 ANSWER = 140
.....5 .....Σ 9r ...r=1
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
975
25,20,5,30
Oh, isn't that a happy little math problem! We take the sum of all the odd multiples of five from 1 to 2007, which is 5 + 15 + 25 + ... + 2005. This sum is 100,040,000. When we divide this by ten, we get a remainder of 0, like a peaceful little stream flowing gently through the forest.