It is: 6+12+18 = 36
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
The first five multiples of 6 are 6, 12, 18, 24 and 30. For them to be common, they need to be compared to another set of multiples.
0, 2, 4, 6, 8.0,2,4,6,8 are the first five multiples of 2
6, 12, 18, 24, 30
5 + 10+15+20=50 ans
It is: 6+12+18 = 36
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
Multiples of 6 are numbers in the 6 times table. So the first 5 multiples of 6 are 6, 12, 18, 24 and 30.
6 + 12 + 18 + 24 + 30 + 36 = 126
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
The first 6 multiples of 5 are: 5, 10, 15, 20, 25, and 30.
The first five multiples of 6 are 6, 12, 18, 24 and 30. For them to be common, they need to be compared to another set of multiples.
30, 60, 90, 120, 150