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T = 2*pi*sqrt(L/g) = 2.006 seconds (approx).



T = 2*pi*sqrt(L/g) = 2.006 seconds (approx).



T = 2*pi*sqrt(L/g) = 2.006 seconds (approx).



T = 2*pi*sqrt(L/g) = 2.006 seconds (approx).
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What will happen to length of a simple pendulum if its time period is doubled?

time period of simple pendulum is dirctly proportional to sqare root of length...


What factors determine the time period of the simple pendulum?

The time period of a simple pendulum is determined by the length of the pendulum, the acceleration due to gravity, and the angle at which the pendulum is released. The formula for the time period of a simple pendulum is T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.


In simple pendulum if string is flexible then what is effect on time period?

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If length of simple pendulem increases constantly during osscillation then what is effct on time period?

If the length of a simple pendulum increases constantly during oscillation, the time period of the pendulum will also increase. This is because the time period of a simple pendulum is directly proportional to the square root of its length. Therefore, as the length increases, the time period will also increase.


What is the time period of a simple pendulum of infinite length?

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What is effect on time period of simple pendulum at centre of earth?

The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.


Why time period of simple pendulum is independent of mass?

The time period of a simple pendulum depends only on the length of the pendulum and the acceleration due to gravity, not the mass of the pendulum bob. This is because the mass cancels out in the equation for the time period, leaving only the factors that affect the motion of the pendulum.


Time period of simple pendulum is three seconds the same pendulum taken at the moon - what will be its new time period?

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What happens to time period of a simple pendulum if a heavy body is attached to it instead of bob?

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What are the factors on which the time period of simple pendulum depends?

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What will be the effect of time period of a simple pendulum if its mass is doubled and its amplitude is halved?

The time period of a simple pendulum is not affected by changes in amplitude. However, if the mass is doubled, the time period will increase because it is directly proportional to the square root of the length of the pendulum and inversely proportional to the square root of the acceleration due to gravity.


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