T = 2pisqrt(L/g) = 2.006 seconds (approx).
time period of simple pendulum is dirctly proportional to sqare root of length...
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
∞
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
ts period will become sqrt(2) times as long.
time period of simple pendulum is dirctly proportional to sqare root of length...
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
∞
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
The period of a simple pendulum is independent of the mass of the bob. Keep in mind that the size of the bob does affect the length of the pendulum.
The period of a simple pendulum of length 20cm took 120 seconds to complete 40 oscillation is 0.9.
ts period will become sqrt(2) times as long.
It would tend towards infinity
They determine the length of time of the pendulum's swing ... its 'period'.
The time period of a simple pendulum is calculated using the following conditions: Length of the pendulum: The longer the length of the pendulum, the longer it takes for one complete back-and-forth swing. Acceleration due to gravity: The time period is inversely proportional to the square root of the acceleration due to gravity. Higher gravity results in a shorter time period. Angle of displacement: The time period is slightly affected by the initial angle of displacement, but this effect becomes negligible for small angles.