13 ? 15
Solve this simultaneous equation by the elimination method: x+y = 12 x-y = 4 Add both equations together: 2x = 16 Divide both sides by 2 to find the value of x: x = 8 Substitute the value of x into the original equations to find the value of y: Therefore: x = 8 and y = 4
x = -1/3 and y = 7/12
12
If we are not given the exact relationship between two variables, it is not possible to find the value of one variable corresponding to the value of the other variable. Let us solve it by the two following methods and see the difference.Method 1When x=3 then y=12i.e., y/x=12/3=4i.e., y=4xWhen x=7, then y=4*7=28Method 2When x=3 then y=12i.e., x+y=3+12=15i.e., y=15-xWhen x=7, y=15-7=8
Insufficient information. What is x when y = 12?
13 ? 15
x+ySince x=4, we can replace the x with a 4:4+ySince y=12, we can replace the y with a 124+12 = 16
x equals -12 and y equals 1/4 of -12, so y = -3.
Solve this simultaneous equation by the elimination method: x+y = 12 x-y = 4 Add both equations together: 2x = 16 Divide both sides by 2 to find the value of x: x = 8 Substitute the value of x into the original equations to find the value of y: Therefore: x = 8 and y = 4
x = -1/3 and y = 7/12
12
If we are not given the exact relationship between two variables, it is not possible to find the value of one variable corresponding to the value of the other variable. Let us solve it by the two following methods and see the difference.Method 1When x=3 then y=12i.e., y/x=12/3=4i.e., y=4xWhen x=7, then y=4*7=28Method 2When x=3 then y=12i.e., x+y=3+12=15i.e., y=15-xWhen x=7, y=15-7=8
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
If: 2x-3y = -15 and x = 4y Then: x = -12 and y = -3
y = 6
15 (x = 135)