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Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
If f(x)=1/x then F(x)=antiderivative of f(x)=ln(|x|) (the natural log of the absolute value of x) There's another way of reading this question. The anti derivative of 1 is x+c. Dividing that by x gives you 1 + c/x
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
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It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
Negative the derivative of f(x), divided by f(x) squared. -f'(x) / f²(x)
The derivative of x divided by 3 is 1/3. This can be found using the power rule of differentiation, where the derivative of x^n is nx^(n-1). In this case, x can be written as x^1, so the derivative is 1(1/3)*x^(1-1) = 1/3.
10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4
if y=7/(x^3)-4/xthenby the quotient ruley'=(((0)(x^3)-(7(3x^2))/((x^3)^2))-(((0x)-(4))/(x^2))
m
d/dx of 6*x^(-1/3) = (-6/3)*x^(-4/3) = -2*x^(-4/3), by power rule
(1/2(x^-1/2))/x
(cos x sin x) / (cos x sin x) = 1. The derivative of a constant, such as 1, is zero.
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