The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
18 and 1
17
No. 8/9 is twice as large.
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
18. 1+8=9 9x2=18
18 1 + 8 = 9 and 9 x 2 = 18
The sum of 1 + 8 is 9.
The sum of 8, 11 and 9 is 28.
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
18 and 1
2n + 8 = 33
It is: 2(8+3) which is 22
17
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }