18. 1+8=9 9x2=18
47 Impossible problem!
8 is the same as the sum of the digits of its cube, 512.
If the sum of a number and 4 is (X + 4) then twice that is 2(X + 4) which is 2X + 8
24
362x(3x6)
18
18 is the only number that matches these criteria.
Yes, unless you include 0.
18 is the only number (other than 0) that is twice the sum of its digits.
the sum of my digits is 6? answer=60
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
Add the digits together. The sum of the digits of 23 is 5.
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
None. The sum of one digit can't be twice the size of the digit.
18 1 + 8 = 9 and 9 x 2 = 18
47 Impossible problem!
8 is the same as the sum of the digits of its cube, 512.