x = 3 and y = 0
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
x=1y=2x+3y=2*1 + 3y=5
x = 3 and y = 2 so the lines intersect at the point (3, 2)
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
x = 3 and y = 0
(3, 2) because x = 3 and y = 2
2x+3y=13 3x-y=3 x=2
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
y=(x-1)/3
5x+3y
4x + 3y=9 x=0 y=3
It is [4m-1, (4m-2)/3]
x=1y=2x+3y=2*1 + 3y=5
-x + 3y = 6 3y = x 6 y = x/3 + 2 So slope = 1/3 and intercept = 2
x = 3 and y = 2 so the lines intersect at the point (3, 2)
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y