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18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
3xy - 3xy = 0
they are noncolinear if there are more than 2 points, if not then any two points always lie on the same line
The expression (4xy - 3xy + 2xy) consists of three terms: (4xy), (-3xy), and (2xy). Each term is a product of the coefficient (a number) and the variable part, which in this case is (xy). The coefficients are 4, -3, and 2, respectively. To combine the like terms, you would simplify the expression to ( (4 - 3 + 2)xy = 3xy).
To find the expression for ((5x - y)(3x^2 - 3xy + 2y^2)), you need to distribute (5x) and (-y) across each term in the second polynomial. This results in: [ 5x(3x^2) - 5x(3xy) + 5x(2y^2) - y(3x^2) + y(3xy) - y(2y^2) ] Simplifying this gives: [ 15x^3 - 15x^2y + 10xy^2 - 3x^2y + 3xy^2 - 2y^3 ] Combining like terms results in: [ 15x^3 - 18x^2y + 13xy^2 - 2y^3 ]
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
It is the same as: 12y^2 -3xy
Collinear points are points that lie on the same line, while coplanar points are points that lie on the same plane.
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
If: x -2y = 1 then x = 1+2y If: 3xy -y^2 = 8 then 3(1+2y)y -y^2 = 8 So: 3y+6y^2 -y^2 = 8 => 3y+5y^2 -8 = 0 Solving the above quadratic equation: y = 1 or y = -8/5 By substitution the points of intersection are at: (3, 1) and (-11/5, -8/5)
Not necessarily. Points may lie in different planes.
Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.