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18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
3xy - 3xy = 0
they are noncolinear if there are more than 2 points, if not then any two points always lie on the same line
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
It is the same as: 12y^2 -3xy
Collinear points are points that lie on the same line, while coplanar points are points that lie on the same plane.
If: x -2y = 1 then x = 1+2y If: 3xy -y^2 = 8 then 3(1+2y)y -y^2 = 8 So: 3y+6y^2 -y^2 = 8 => 3y+5y^2 -8 = 0 Solving the above quadratic equation: y = 1 or y = -8/5 By substitution the points of intersection are at: (3, 1) and (-11/5, -8/5)
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
Not necessarily. Points may lie in different planes.
Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.Three or more points are collinear if they lie on the same straight line.
-3xy is a monomial where x and y are variables and -3 is the coefficient of the monomial.If we know the value of y, we have to substitute it for y, and we say that -3(y-value) is the coefficient of x.
1,3,x,y,3x,3y,xy,3xy