slope is -4/5 or -0.8 and there is no y intercept
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
y=x+5
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
69
slope = -1
-3/5
slope is -4/5 or -0.8 and there is no y intercept
10x+5y = 25 5y = -10x+25 y = -2x+5 Therefore: the slope is -2 and the intercept is 5
45
It is: minus 1.25
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
y = -1.2x-3 in slope intercept form
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
It is 3 and the slope is 3/5