10
9 and -1 are a couple of numbers, not an equation.
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
x = 2 and x = -5
No. It's a quadratic equation, and it has two solutions.
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
3
x = 2 and x = -5
It has two equal solutions for x which are x = 2 and x = 2
There are infinitely many solutions to 11x - 99 = 11(x - 9)
No. It's a quadratic equation, and it has two solutions.
The discriminant is 1-4*2*(-1) = 1+8 = 9. This is greater than 0 so there are 2 real solutions.
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)