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How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
What are the solutions for the quadratic equation x2 minus 8x equals 9?
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
Is 4y squared plus 9 equals - 4 a linear equation?
No. It's a quadratic equation, and it has two solutions.
