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How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
What are the solutions for the quadratic equation x2 minus 8x equals 9?
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
Is 4y squared plus 9 equals - 4 a linear equation?
No. It's a quadratic equation, and it has two solutions.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
What are the solutions for the quadratic equation 8x x2 - 9?
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
How many solutions does the equation have?
The number of solutions an equation has depends on the nature of the equation. A linear equation typically has one solution, a quadratic equation can have two solutions, and a cubic equation can have three solutions. However, equations can also have no solution or an infinite number of solutions depending on the specific values and relationships within the equation. It is important to analyze the equation and its characteristics to determine the number of solutions accurately.
What are the solutions for the quadratic equation x2 minus 8x equals 9?
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
What are four solutions of the equation y equals -3x-6?
3
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
How many real and imaginary solutions does the equation 2x2 -7x plus 9 equals x plus 1 have?
It has two equal solutions for x which are x = 2 and x = 2
How many solutions are there to the equation below 11x - 99 11(x - 9)?
There are infinitely many solutions to 11x - 99 = 11(x - 9)
Is 4y squared plus 9 equals - 4 a linear equation?
No. It's a quadratic equation, and it has two solutions.
How many real solutions are there to the equation show below 2x 2 plus x-1 equals 0?
The discriminant is 1-4*2*(-1) = 1+8 = 9. This is greater than 0 so there are 2 real solutions.
What is 9 - (2x - 2) 9 - 3x?
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
What are the solutions of the simultaneous equations of x squared -xy -y squared equals -11 and 2x plus y equals 1?
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
