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Q: When x6y12 and x8y10 what is the relation of x and y?
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What inverse relation means?

Two variables, X and Y, are in inverse relation if X*Y = a constant.


What are function and relation?

A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.


What is it called if any vertical line crosses the graph of a relation more than once the relation is not a function?

The Vertical Line Test An example might be x=cos(y). At any value of x between -1 a nd +1 (a vertical line on the graph) this is multivalued (and so it is called "multivalued"). The relation is a function, because given y you can calculate x. x is a function of y. The relation between y and x can also be written y=cos-1(x) "y is the angle whose cosine is x". From that point of view you can say " y is not a function of x" because for each x, there is more than one y that satisfyies the equation. To summarize, in this example x is a function of y but y is not a function of x.


What are the properties of the ''less than or equal to'' relation?

The relation ''less than or equal to," written as ≤, has the following three properties on the set of real numbers, R:1) x ≤ x for any x Є R2) If x ≤ y and y ≤ x then x = y for any x, y Є R3) If x ≤ y and y ≤ z then x ≤ z for any x, y, z Є RSee the corresponding related links for basic set theory and the definition of a relation.Also, this relation is an example of a partial ordering relation, see the corresponding related link for more information.


What is the range of the relation y equals to absolute value of x to 4?

y=|x|/4 The range is [0 , ∞ )

Related questions

What inverse relation means?

Two variables, X and Y, are in inverse relation if X*Y = a constant.


What are function and relation?

A function is an equation that gives a unique answer. A relation does not. Example: y = 3x + 1 is a function. If I give you x, you can determine y. And that y is unique to that x. So if x = 1, you know y = 4. No other of x gives y = 4 as an answer. So y = 3x + 1 is a function. Example: y = 4x2. So if I give you x = 1, y = 4. But y = 4 if I also give you x = -1. So y = 4x2 is not a function, it is a relation.


How do you tell if a set has aTransitive relation?

iff (x,y)belongs to R and (y,x)belongs to R then x=y


Is the domain the x or the y axis?

The domain of a relation is the X axis.


What is it called if any vertical line crosses the graph of a relation more than once the relation is not a function?

The Vertical Line Test An example might be x=cos(y). At any value of x between -1 a nd +1 (a vertical line on the graph) this is multivalued (and so it is called "multivalued"). The relation is a function, because given y you can calculate x. x is a function of y. The relation between y and x can also be written y=cos-1(x) "y is the angle whose cosine is x". From that point of view you can say " y is not a function of x" because for each x, there is more than one y that satisfyies the equation. To summarize, in this example x is a function of y but y is not a function of x.


What is used to show relationship between two variable?

In mathematics? This is what's called a relation. For example, the relation y=4x shows that for any given x value, the value of y is four times as great. If y is equal to 8 and the relationship between y and x can be shown by the relation y is equal to four times x, x must equal 8 divided by four. Eight divided by four is 2, therefore x is equal to 2. If x is equal to 6 and the relation ship between y and x can be shown by the relation y is equal to four times x, y must equal 6 multiplied by four. Six multiplied by four is 24, therefor y is equal to 24.


What is an inverse relationship between x and y?

That depends on the original relation. For any relation y = f(x) the domain is all acceptable values of x and the range, y, is all answers of the function. The inverse relation would take all y values of the original function, what was the range, and these become the domain for the inverse, these must produce answers which are a new range for this inverse, which must match the original domain. IE: the domain becomes the range and the range becomes the domain. Ex: y = x2 is the original relation the inverse is y = =/- square root x Rules to find the inverse are simple substitute x = y and y = x in the original and solve for the new y. The notation is the original relation if y = f(x) but the inverse is denoted as y = f -1(x), (the -1 is not used as an exponent, but is read as the word inverse)


What are the properties of the ''less than or equal to'' relation?

The relation ''less than or equal to," written as ≤, has the following three properties on the set of real numbers, R:1) x ≤ x for any x Є R2) If x ≤ y and y ≤ x then x = y for any x, y Є R3) If x ≤ y and y ≤ z then x ≤ z for any x, y, z Є RSee the corresponding related links for basic set theory and the definition of a relation.Also, this relation is an example of a partial ordering relation, see the corresponding related link for more information.


What are nonlinear relationships?

The relation between two variables, x and y, is linear if the expression can be expressed in the form of y = ax + b, where a and b are constants. Any higher order terms will render the relation non-linear. For example, y = x^2 y = sqrt (x) So are the following: y = log (x) y = exp (x) You get the idea.


What is the range of the relation y equals to absolute value of x to 4?

y=|x|/4 The range is [0 , ∞ )


Is Inequality an equivalence relation?

No. It is not transitive. x ≠ y and y ≠ z does not imply that x ≠ z


What is the derivative of x-y?

The partial derivative in relation to x: dz/dx=-y The partial derivative in relation to y: dz/dy= x If its a equation where a constant 'c' is set equal to the equation c = x - y, the derivative is 0 = 1 - dy/dx, so dy/dx = 1