144, 156
60
164.
15, since 15*2 = 9*2 + 12*2
45
500
615, 492 and 369
No, the multiple of any random triple is not a Pythagorean triple.
If you mean 3, 4 and 5 then yes it is a Pythagorean triple
Nearly but not quite a Pythagorean triple
There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.
The Pythagorean thereom is a^2+b^2=c^2. So, you can tell if they are a Pythagorean triple by seeing if the two smaller numbers squared equal the largest number squared. Example. Are 3,4, and 5 a Pythagorean triple? 3^2= 9. 4^2= 16. 5^2= 25. 9+16=25, so they are a triple.
What is the value of x if (13, 84, x) is a Pythagorean triple?
No, the numbers 9, 40, and 41 do not form a Pythagorean triple. To be a Pythagorean triple, the equation (a^2 + b^2 = c^2) must hold true, where (c) is the largest number. In this case, (9^2 + 40^2 = 81 + 1600 = 1681), and (41^2 = 1681), so (9^2 + 40^2 = 41^2). Therefore, 9, 40, and 41 do form a Pythagorean triple.