164.
15, since 15*2 = 9*2 + 12*2
45
500
615, 492 and 369
No, the multiple of any random triple is not a Pythagorean triple.
Nearly but not quite a Pythagorean triple
If you mean 3, 4 and 5 then yes it is a Pythagorean triple
There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.
The Pythagorean thereom is a^2+b^2=c^2. So, you can tell if they are a Pythagorean triple by seeing if the two smaller numbers squared equal the largest number squared. Example. Are 3,4, and 5 a Pythagorean triple? 3^2= 9. 4^2= 16. 5^2= 25. 9+16=25, so they are a triple.
What is the value of x if (13, 84, x) is a Pythagorean triple?
If p and q are integers, then a = p2 - q2 b = 2pq, and c = p2 + q2 form a Pythagorean triple. Furthermore, if p and q are co-prime then the triple is primitive Pythagorean.