It's not true. As with all solid figures, polyhedra have volume and surface area.
Cell have a greater surface area to volume rations than a larger cell.
True.
The answer is TRUE.
Concept The surface-area-to-volume ratio is calculated by dividing the surface area by the volume of any object. If you know the formula for the surface area and the volume of an object, then simply compute (surface area) / (volume) to calculate the surface-area-to-volume ratio. The actual surface-area-to-volume ratio of any object depends upon that object's shape and geometry. Cube Consider a cube with equal sides of length x. The cube has six faces (top, bottom, left, right, front, back), and each face has a surface area of x2, so the total surface area of the cube is 6x2. The volume of the cube is x3. So the surface-area-to-volume ratio for a cube is 6x2 / x3, which can be reduced to 6/x. This surface-area-to-volume ratio, 6/x, holds true for all cubes. Let's test this ratio. Consider a cube that has a 1 cm length on all sides. The surface area is 6 sides of 1 cm x 1 cm (6 cm2), and the volume is 1 cm x 1 cm x 1 cm (1 cm3). Dividing the surface area by the volume gives a surface-area-to-volume ratio of 6 (which is 6/1). If the length of the cube sides is 6 cm, then the surface area is 6 sides of 6 cm x 6 cm (216 cm2) and the volume is 6 cm x 6 cm x 6 cm (216cm3), so the surface-area-to-volume ratio is 216/216, or 1 (which is 6/6). If the length of the cube side is 12 cm, then the surface area is 6 sides of 12 cm x 12 cm (864 cm2) and the volume is 12 cm x 12 cm x 12 cm (1728 cm3), so the surface-area-to-volume ratio is 864/1728, or 0.5 (which is 6/12). We can empirically verify that this surface-area-to-volume ratio for a cube is therefore 6/x. Sphere Consider a sphere (a round ball) of radius r. The surface area is 4 PIr2, whereas the volume is (4/3)PIr3. So the surface-area-to-volume ratio of a sphere is (4 PIr2) / [(4/3)PIr3], which can be reduced to 3/r. As in the cube, the surface-area-to-volume ratio of 3/r holds true for all spheres. In the previous description, the symbol 'PI' is meant to represent Pi, or 3.1415 ... T Irregular Objects For irregular objects, such as a rectangular prism (a box) with different lengths in each dimension, the surface-area-to-volume ratio must be calculated for each shape. Consider a box with dimensions of l (length), w (width), and h (height). Like the cube, the box has six faces, but it is easier to consider it as three face pairs (front/back, left/right, and top/bottom). The surface area of both faces in a pair are the same (the front face has the same surface area as the back face). So the surface area of the box is: A = 2(l x w) + 2(w x h) + 2(l x h), or 2( (l x w) + (w x h) + (l x h) ). The volume is: V = l x w x h So the surface area to volume ratio (A/V) of a box is: 2( (l x w) + (w x h) + (w x h) ) / (l x w x h). The surface-area-to-volume ratio of a cylinder (like a soup can) is: ( (2 PI r2) + (2 PI r h) ) / (PI r2h) Where r is the radius of the circle on the top and bottom of the cylinder, h is the height of the cylinder, and. PI is Pi, or 3.1415 ... Unlike regular objects, such as the cube or sphere, no further simplification of the box's or cylinder's surface-area-to-volume ratio equation exists. The above appropriate equations must be applied to each box or cylinder separately.
It's not true. As with all solid figures, polyhedra have volume and surface area.
Although they do not increase at the same rate, as the surface area increases the volume increases slowly.
Cell have a greater surface area to volume rations than a larger cell.
true. As the candy gets smaller the ratio of surface area to volume increases.
True. As a cell grows in size, its volume increases faster than its surface area. This is because volume increases cubically with the size of the cell (length x width x height), while surface area increases squared with the size of the cell (length x width). This can lead to issues with nutrient exchange and waste removal if the cell becomes too large.
Yes, as cell surface area increases, the cell volume increases at a faster rate. This is because the surface area to volume ratio decreases as the cell grows larger, which can affect the efficiency of nutrient uptake and waste removal within the cell.
If a cell gets too large, it may struggle to efficiently transport nutrients and waste products across its membrane due to its limited surface area relative to its volume. This can lead to issues with maintaining proper cellular functions and viability.
True. As a cell grows larger, its volume increases more quickly than its surface area. This is because volume is determined by the cube of the linear dimension (x^3), while surface area is determined by the square of the linear dimension (x^2). This can lead to issues with nutrient and waste exchange as the cell grows larger.
The relationship between the percent volume (not reached by the stain) and the surface area-to-volume ratio would be that the bigger the agar cube size (surface area to volume ratio), the bigger the percent volume. This is true because resources need to travel a farther distance through the cell ("cover more ground", so to speak) in order to be evenly distributed through the cell.
Area the measure of the two - dimensional space enclosed in a shape while volume is the measure of the three - dimensional space in enclosed in a shape. this is true said blue waffle man.Area has two dimensions. Volume has three. Also are is a measure of a surface and Volume is a space occupied by a gas or liquid.Volume is measured in cubic units and area is measured in square units.Area is surface measurement. Volume is measurement of the surface area x depth or height (think of capacity to describe volume).
No. There is no one single expression for the rate of a chemical reaction. It depends on many factors. It is true, however, that the greater the surface area, the greater would be the rate of reaction, but it isn't EQUAL to SA/Volume.
the horizontal cross-sections of the prisms at the same height must have the same area. (APEX)