there is a 50% chance that the offspring will be tall.
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.
1. Put your group of numbers in order from least to greatest2. Keep crossing out 1 number from each side of the line3. If you have crossed out an equal number on both sides, and there is one left in the middle, it's your median!If there is not an equal number, you take the 2 numbers that are left, add them, multiply by 2, and there's your median!Definition: Median means middle
First you sort them from least to greatest and you pick the number in the middle. If the number of numbers is even and you have two numbers in the middle you add them together and then divide the sum by 2.************************************************When writing the numbers from smallest to greatest, write repeated numbers next to each other in the correct positions and cross out as usual...1,1,2,4,5,5,5,6,9write the numbers like socross out as normal (italicized numbers are crossed out)1,1,2,4, 5 5,5,6,9One of the 5s is the middle number so that is your median
100%
of two different phenotypes
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
The possible genotypes of parents who are heterozygous would be found using a punnet square. The outcome would be 50 percent heterozygous dominant, 25 percent homozygous dominant, and 25 percent homozygous recessive.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
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A pretty bow
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
In such a cross, the F1 plants will always be tall, because that is the dominant allele. In the cross described, a homozygous dominant plant was crossed with a homozygous recessive plant; a cross that produces 100% heterozygous offspring. (AaBbCc)
The offspring would have a 50% chance of being heterozygous and showing the dominant trait and a 50% chance of being homozygous for the recessive trait.
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white. So, the homozygous red flower will be red, the homozygous white flower will be white, and the heterozygous flower will be pink. So there are three possible phenotypes in incomplete dominance. There are also no dominant or recessives genotypes.