The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
25%
25% or 1 out of 4 (You can use a Punnett Square for that and/or other questions like it.)
false
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
The homozygous dominant individual can only pass on the dominant allele and the homozygous recessive individual can only pass on the recessive allele, therefore all offspring will be heterozygous and have the dominant phenotype.
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
If the individual heterozygous for a cleft chin mates with an individual homozygous for chin without a cleft, their offspring can inherit their recessive allele for chin without a cleft. This would make their offspring homozygous recessive for chin without a cleft. The probability of this occurring is 50%.
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
To determine if a particular plant is homozygous or heterozygous, you would need to perform a test cross with a homozygous recessive individual. If the offspring display the recessive trait, the original plant would likely be heterozygous. If all offspring exhibit the dominant trait, the original plant would likely be homozygous dominant.
The offspring would most likely have a 50% chance of inheriting the heterozygous trait and a 50% chance of inheriting the homozygous recessive trait.
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.
The probability of offspring for two heterozygous dogs (Aa x Aa) is 25% homozygous dominant (AA), 50% heterozygous (Aa), and 25% homozygous recessive (aa) based on Mendelian genetics principles.
They are the same