ok let's try this!
on any given date, probability that there is a student with a birthday is 30/365, so prob. that two students have that birthday is (30/365)^2. Tell me if I'm wrong, somebody!
So the problem that this does NOT happen is 1-(30/365)^2 which is 0.9932445...
I'm not sure about this next bit:
there are 365 days in which this probably won't occur, does that make a difference?
About 83.2%The probability that non of the 36 students have the same birthday (not consideringFebruary 28 of the leap year) is given by the following relation:P(non out of n have same bd) = Π1n-1 [(365-i)/365]P(non out of 36 have same bd) = (364/365)(363/365)(362/365) ... (331/365)(330/365) == 0.167817892.. ≈ 16.8%So the probability of at least 2 having the same birthday is about 1 - .168 = 0.832 =83.2%
.9^27, or approximately .058 = 5.8%
The probability of this is based heavily on whether or not said best friend is even in the class. If both are in, it's a 1/870 chance.Ê
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
13 out of 20
It depends on how big the class is.
A birthday attack is a method of code decryption which exploits the birthday paradox - that which explains that within a class of 30 students, there is an assumed probability of two sharing the same birthday of 70 percent.
About 83.2%The probability that non of the 36 students have the same birthday (not consideringFebruary 28 of the leap year) is given by the following relation:P(non out of n have same bd) = Π1n-1 [(365-i)/365]P(non out of 36 have same bd) = (364/365)(363/365)(362/365) ... (331/365)(330/365) == 0.167817892.. ≈ 16.8%So the probability of at least 2 having the same birthday is about 1 - .168 = 0.832 =83.2%
The probability is 15/25 = 3/5
The probability is the number of girls divided by the number of students, so 12/22, or 6/11
.9^27, or approximately .058 = 5.8%
The probability of this is based heavily on whether or not said best friend is even in the class. If both are in, it's a 1/870 chance.Ê
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
I am not going to help you cheat in math class!!!!!!!!!!!!!
The probability is 15/25 = 3/5
13 out of 20
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.