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A coin is flipped 3 times. What is the probability of getting at least 1 tails?
Wiki User
∙ 14y ago
7/8
P(all heads) = (1/2)*(1/2)*(1/2)=(1/8).
P(at least one tails) = 1-P(all heads) = 7/8.
Another (more time-consuming) way to get the same result:
P(all tails) = (1/2)^3=1/8
P(exactly two tails) = 3*(1/2)^3=3/8
P(exactly one tails) = 3*(1/2)^3=3/8
P(at least one tail) = P(all tails) + P(exactly two tails) + P(exactly one tails) = 7/8
Wiki User
∙ 14y ago
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What is the probability of getting a least one tail when tossing eight fair coins?
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
What is the probability of obtaining at least one head when a coin is flipped four times?
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375
What is the probability of getting at least two tails?
That depends how many times you flip the coin.
What is the probability of flipping three tails when three coins are flipped?
The probability of flipping three tails with three coins is (1 in 2)3 or 1 in 8 or 0.125.
What is the probability of getting 2 tails if 3 fair coins are tossed?
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
When a coin is flipped what is the probability that it will come up tails?
The side heads is slightly heavier giving it a greater likely hood of landing on tails.
What is the probability of getting a least one tail when tossing eight fair coins?
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
What is the probability of obtaining at least one head when a coin is flipped four times?
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375
What is the probability of obtaining two tails or more if three coins are flipped?
It is 0.5
What is the probability of getting at least two tails?
That depends how many times you flip the coin.
What is the probability of flipping three tails when three coins are flipped?
The probability of flipping three tails with three coins is (1 in 2)3 or 1 in 8 or 0.125.
The probability of getting a six on a six sided die and then getting a tails?
The probability of getting a six on a six sided die and then getting a tails is zero. There is no tails on a die.
2 coins are flipped. What is the probability of landing one heads and one tails?
It is 1/2.
Judy tosses a coin 4 times What is the probability of getting at least 2 tails?
50/50
What is the probability of flipping 5 coins and getting all tails?
The probability of getting all tails is 1/25 = 1/32
What is the probability of getting 2 tails if 3 fair coins are tossed?
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
What is the probability of obtaining atleast one tail when a coin is flipped six times?
you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=
