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When a die is rolled find the probability of getting a a number larger than 2?

If it is a fair die that is rolled once, then the probability is 2/3.


A die is rolled once What is the probability of not getting number 2?

5/6 = 83.3%


A 1-6 number cube is rolled what is the probability that the number rolled is a two or a five?

7


If a number cube is rolled what is the probability that the number rolled will be greater than 3?

It is 1/2 if it is a fair number cube which is rolled once.


When a number cube is rolled once what is the probability of getting an odd number greater than five?

it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...


A six sided die is rolled once what is the probability of rolling a prime number?

1 out of 2


What is the probability of rolling 6 or less if two dice are rolled once?

The probability is 1, if the dice are rolled often enough.


if a die is rolled once what is the probability of getting more than 3?

There is a 1 in 2 chance, so 1/2.


If a die is rolled once what is the probability of rolling a number between and including one and six?

The probability is 1. It is a certainty that you will roll a number between and including one and six. The probability of rolling each individual number is 1/6.


A number cube is rolled once find each probability write your answer as a fraction a decimal and a percent?

P(1 or 6)


What is the probability of getting a number greater than 4 when rolling a single die once?

the probability is 2/6


A dice is tossed thrice find the probability of getting an odd number at least once?

To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).

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