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Convert to Std Normal Distribution and calculate (or use java script) area under curve for probability (see related links). Z55= (55-55)/6 = 0 and Z65 = (65-55)/6 = 1.667. We need area under curve for Z from 0 to 1.667. From javascript = use between 0 & 1.667, obtain .4522 or 45.22% probability. From Table; 0.9525-0.5 = .4525 = 45.25% (use above; more accurate but this IS close).

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Q: A normal distribution with a mean of 55 and a standard deviation of 6 is evaluated to solve a business problem. What is the probability that any value in the population is between 55 and 65?
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