They are {0, x, 11-x, 11}, where x is any number between 2 and 6.5
order from smallest to largest:(w +x + y + z)/4 = 6 (mean)(x + y) /2 = 6.5 (median)z-w = 11 (range)solve w = 0 and z = 11x + y = 13 x = 6y = 7;0,6,7,11
A quartile is a given section in a range of data. To find the quartile, you must first find the median. Then find the "median of the median", using these to separate your data into sections, giving you a total of four sections of data.
There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.
Assuming positive integers, and no leading zeros, the range of five digit numbers is 10000 to 99999. The ones that end in zero can be found by taking the four digit numbers: 1000 to 9999 and multiplying each by ten. {1000,1001, 1002, ...9999}, multiplied by ten is {10000,10010,10020,....99990}. There are 9000 of them.
85 91 48 98 99 91 90 84 91 To find the median, first rearrange the numbers in rank order. That is from lowest to highest. Hence 48,84,85,90,91,91,91,98,99. Next we notice that there are nine terms. To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term. NB If you had left the numbers in the original order, the median would have been '99', which is incorrect. NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term. Hope that helps !!!!
A 75 B 2 C 44 D 27 E 8 F 91 G 18 H 46 I 38 J 62? First put the numbers/terms in rank order. That is lowest to highest, or vice versa. 2,8,18,27,38,44,46,62,75,91. The MEDIAN is the absolute middle middle number. Since there are an even number of terms, there is no absolute middle term. So we take the two nearest to middle terms, they are 38 & 44. (NB This leaves four terms to the left of 38, and four terms to the right of 44. We then add the two terms and divide by '2'. Hence ( 38 + 44) / 2 = 82/2 = 41 '41' is the median.
The first four positive integers of 13 are : 26, 39, 52, 65
The positive integers up to 4 are: 1, 2, 3, and 4. This is a total of four positive integers.
The final result is positive.
1,3,5,7
This is impossible with positive integers. However, four numbers separated by a difference of 1 with a sum of -92 are: -21.5 -22.5 -23.5 -24.5
Among positive integers, 6
The sign of the product of four integers depends on the signs of the individual integers. There are 4 cases: 1) When all 4 integers share the same sign and all are non-zero (either all are positive or all are negative), the product is positive. 2) When 3 of the 4 integers share the same sign and all are non-zero (3 are positive and 1 is negative; or 3 are negative and 1 is positive), the product is negative. 3) When 2 of the integers are positive non-zero and the other 2 of the integers are negative non-zero, the product is positive. 4) If even one of the integers is zero, the product is zero (no sign - it is neither positive nor negative).
No, only positive integers are considered counting numbers.
Four random, positive, one-digit integers.
There are four.
They are four positive integers in decreasing order of magnitude.
Four unique pairs.