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They are {0, x, 11-x, 11}, where x is any number between 2 and 6.5

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7y ago
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7y ago

order from smallest to largest:(w +x + y + z)/4 = 6 (mean)(x + y) /2 = 6.5 (median)z-w = 11 (range)solve w = 0 and z = 11x + y = 13 x = 6y = 7;0,6,7,11

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Q: A set of four positive integers with a mean of 6 median of 6.5 and a range of 11?
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Continue Learning about Statistics

What is a quartile in a math problem?

A quartile is a given section in a range of data. To find the quartile, you must first find the median. Then find the "median of the median", using these to separate your data into sections, giving you a total of four sections of data.


How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?

There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.


How many 5 digit numbers that end with 0 are there?

Assuming positive integers, and no leading zeros, the range of five digit numbers is 10000 to 99999. The ones that end in zero can be found by taking the four digit numbers: 1000 to 9999 and multiplying each by ten. {1000,1001, 1002, ...9999}, multiplied by ten is {10000,10010,10020,....99990}. There are 9000 of them.


What is median of 85 91 48 98 99 91 90 84 91?

85 91 48 98 99 91 90 84 91 To find the median, first rearrange the numbers in rank order. That is from lowest to highest. Hence 48,84,85,90,91,91,91,98,99. Next we notice that there are nine terms. To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term. NB If you had left the numbers in the original order, the median would have been '99', which is incorrect. NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term. Hope that helps !!!!


What is the median of the following string of values A 75 B 2 C 44 D 27 E 8 F 91 G 18 H 46 I 38 J 62?

A 75 B 2 C 44 D 27 E 8 F 91 G 18 H 46 I 38 J 62? First put the numbers/terms in rank order. That is lowest to highest, or vice versa. 2,8,18,27,38,44,46,62,75,91. The MEDIAN is the absolute middle middle number. Since there are an even number of terms, there is no absolute middle term. So we take the two nearest to middle terms, they are 38 & 44. (NB This leaves four terms to the left of 38, and four terms to the right of 44. We then add the two terms and divide by '2'. Hence ( 38 + 44) / 2 = 82/2 = 41 '41' is the median.

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