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85 91 48 98 99 91 90 84 91
To find the median, first rearrange the numbers in rank order. That is from lowest to highest.
Hence
48,84,85,90,91,91,91,98,99.
Next we notice that there are nine terms.
To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term.
NB If you had left the numbers in the original order, the median would have been '99', which is incorrect.
NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term.
Hope that helps !!!!
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What is the median of these numbers 82 85 87 89 91 93 96 97?
The median is (89 + 91)/2 = 90
What is the mean median and mode of 60 70 75 78 80 80 83 85 87 90 90 90 90 93 95 95 98 100?
The mean is 85.5 The median is 88.5 The mode is 90
What are the mean median mode and range of 100 90 85 90 80 75 80 90?
100,90,85, 90,80,75,80.90. Rearrange the terms in rank order. 75,80,80,85,90,90,90,100. MEAN : Add all the terms together and divide by the number of terms. Hence:- (75+80+80+85+90+90+90,+100)/8 => 690/8 = 86.25 MEDIAN : Is the Absolute middle term. Since there are an even number of terms, we take the two middle terms, which are 85 & 90. (NB This leaves three terms to the left of '85' and three terms to the right of '90'. ). Add these two terms and divide by '2'. Hence (85+90) / 2 = 87.5 MODE : Is the most frequent term. The one term that appears most often. In this case it is '90', as there are three lots of '90', but only two lots of 80, and only one each of the remaining terms. = 90. .
What is the mean for 80 85 76 70 87 80 90 80 90?
82.
What is the interquartile range?
Like the standard deviation, the interquartile range (IQR) is a descriptive statistic used to summarize the extent of the spread of your data. The IQR is the distance between the 1st quartile (25th percentile) and 3rd quartile (75th percentile). Q3 - Q1 = IQR To find these numbers you must divide your data set in half, and find the median of each half and that will be your Q1 and Q3. If you have an odd number, then EXCLUDE the median of the entire set, so as follows: For example, take the following dataset: 3 5 7 8 9 21 40 90 120 We exclude the 9 as the median of the whole set and the 1st quartile is 6 (5+7 divided by 2) and the 3rd quartile is 65 (40+90 divided by 2), making the IQR = 65-6=59. OR If you have this set: 3 5 7 8 40 90 120 We exclude the 8 as the median of the whole set and the 1st quartile is 5 and the 3rd quartile is 90. (90 - 5 = 85.)
What is the median of 72 90 85 84 91 78 94 86 82 78 86 78 95 90 88?
The median is 86.
What is the median of 80 85 90 90 95 100?
90
What is the median of 90 85 80 90 95 90 and 100?
90
What is the median of 40 65 80 90 90 100?
85
What is the median of 75 75 75 85 80 90 and 90?
80
What is the median of 90 85 70?
It is 85, as that is the middle number when they are arranged in numerical order.
What is the median of 84 86 87 84 86 89 90 87 87 84 86?
Well, darling, the median is the middle number when the numbers are listed in order. So, in this case, when you line up those numbers in numerical order, the middle number is 86. Voilà, that's your median.
What is the median of 60 95 100 75 65 85 90 70?
Median of the set = arithmetic mean of 75 and 85 = 80
What is the median of 75 80 90 100?
It is 85, the middle value, between 80 and 90.
What is 92 - 84?
8
What is the median of 86 90 85 94 and 80?
the median is 86. What you do is put the numbers in order from least to greatest and cross one off from each side till you get to the middle number. 80 85 86 90 94
What is the median of 90 88 88 87 84 95 90 80 98 and 100?
When the data is arranged in ascending order, the middle numbers are 88 and 90. Take the mean of these, which is 89, as the median.
