Assuming that it is a regular shaped spinner, the probability is 1/6*1/6 = 1/36
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].In words: Probability of A given B compliment is equal to the Probability of A minus the Probability of A intersect B, divided by 1 minus the probability of B.
It means multiply, Probaility of A and B means probability of A multiplied by probability of B.
Given two events, A and B, the probability of A or B is the probability of occurrence of only A, or only B or both. In mathematical terms: Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B).
If the probability of A is p1 and probability of B is p2 where A and B are independent events or outcomes, then the probability of both A and B occurring is p1 x p2. See related link for examples.
The probability of event A occurring given event B has occurred is an example of conditional probability.
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The probability of landing on A in one spin is ( \frac{1}{4} ). To find the probability of landing on A twice in a row, you multiply the probabilities of each independent event: ( \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} ). Therefore, the probability of landing on A twice in a row is ( \frac{1}{16} ).
P(A given B')=[P(A)-P(AnB)]/[1-P(B)].In words: Probability of A given B compliment is equal to the Probability of A minus the Probability of A intersect B, divided by 1 minus the probability of B.
It means multiply, Probaility of A and B means probability of A multiplied by probability of B.
Given two events, A and B, the probability of A or B is the probability of occurrence of only A, or only B or both. In mathematical terms: Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B).
The probability is 1/b.
a and b both have the probability of 3/4
If the probability of A is p1 and probability of B is p2 where A and B are independent events or outcomes, then the probability of both A and B occurring is p1 x p2. See related link for examples.
If A and B are independent, then you can multiply the two probabilities
Yes. AND operation = f(A,B) = AB = A'f(0,B) + Af(1,B) = A'(0B) + A(1B) = A'0 + AB OR operation - f(A,B) = A+B = A'f(0,B) + Af(1,B) = A'(0+B) + A(1+B) = A'B + A1 NOT operation - f(A) = A' = A'f(0) + Af(1) = A'(1) + A(0)
Use the spinner and go on tracks then press A to jump off.
The probability of event A occurring given event B has occurred is an example of conditional probability.