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You spin the pointer on the spinner. find the probability the pointer will land on 3?

To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.


If the spinner is spun 20 times how many times would you expect to land on 3?

To determine how many times you would expect to land on 3 after spinning the spinner 20 times, you need to know the probability of landing on 3 in a single spin. If the spinner has an equal number of sections, you can find the probability by dividing the number of sections that include 3 by the total number of sections. Multiply that probability by 20 to get the expected number of times landing on 3. For example, if the spinner has 4 equal sections, the expected number would be (20 \times \frac{1}{4} = 5).


A five color spinner with equal sections of red blue green yellow and orange is spun What is the probability of getting no reds in six spins?

If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.


What is the probability of spinning a spinner that has 5 equal sections marked 1 through 5 and landing on an even number?

The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.


What is the probability of the spinner landind on B then C?

To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.

Related Questions

You spin the pointer on the spinner. find the probability the pointer will land on 3?

To find the probability of the pointer landing on 3, you need to know the total number of equal sections on the spinner. If the spinner has ( n ) sections, and one of them is labeled 3, the probability is calculated as ( \frac{1}{n} ). For example, if there are 8 sections, the probability would be ( \frac{1}{8} ). Without knowing the total number of sections, the exact probability cannot be determined.


A Spinner with 8 equal sections labeled 1 through 8 landing on a number less than 9?

100%


A five color spinner with equal sections of red blue green yellow and orange is spun What is the probability of getting no reds in six spins?

If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.


What is the probability of spinning a spinner that has 5 equal sections marked 1 through 5 and landing on an even number?

The spinner has five equal sections marked 1 through 5, with the even numbers being 2 and 4. There are 2 favorable outcomes (landing on an even number) out of a total of 5 possible outcomes. Therefore, the probability of landing on an even number is ( \frac{2}{5} ) or 40%.


What is the probability of the spinner landind on B then C?

To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.


A spinner has 5 equal sections There are 3 green sections and 2 yellow sections The spinner is spun 30 times Which proportion can be used to find the number of times that the spinner lands on green?

3/5=g/30


Chris spins a spinner with 8 equal sections. Each section is labeled with a 1 2 or 3. Use results 1 equals 11 and 2 equals 60 and 3 equals 25 to predict how many sections are labeled with each number?

There is 1 section numbered 1, 5 sections numbered 2 and 2 sections numbered 3.


A five color spinner with equal sections of red blue green yellow and orange is spun What is the probability of getting a blue on the twelfth spin?

the same as it is the first time 1/5


If a spinner is divided into 4 equal parts 2 colored blue one green and one red what is the probability that you would spin a blue?

The chance of receiving a blue result is 2 in 4, in other words 50%.


What is the probability of a number less than 6 on the number cube followed by a number equal to 6 on the spinner?

The probability is(5 times the number of 6s on the spinner/6 timesthe total number of different positions on the spinner)


If you spin the spinner two times what is the probability that the spinner will land on the black region twice?

To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.


A spinner has equal regions numbered 1 through 21 What is the probability that the spinner will stop on an even number or a multiple of 3?

17 out of 21