The probability is approx 0.81
The probability that both will be hopelessly romantic is .0081 .009^2 = .0081
probability of 75 percent = 3/4
0.3456
Yes.
the probability of a house will be burglarized is = 5% which is = .05 the probability of a house will NOT be burglarized is = (1 - .05) the probability of a second house will NOT be burglarized is = (1-.05)*(1-.05)= (1-.05)^2 the probability of a third house will NOT be burglarized is= (1-.05)*(1-.05)(1-.05)= (1-.05)^3 so, the probability of NONE = (1-.05)^10 = .598736939 = .5987
The probability is 10 percent.
Only one selected 68%
Using the Poisson approximation, the probability is 0.0418
Approx 0.0287
It is 0.73 = 0.343
The probability that both will be hopelessly romantic is .0081 .009^2 = .0081
The probability of 33.3 percent is 0.333.
probability of 75 percent = 3/4
Approximately 28.4%. This is based on 6 randomly selected teams from the 2008-2009 season.
You multiply the probability by 100.
Refer back to the first clause. The answer is 50 per cent!
0.3456