(.81)(.81)(.81)(.81)(.81)(.81) = .2824
p = 1 - .2824 = .7176
answer = .7176
The answer is 50%.
Well, honey, if 80% of California drivers wear seat belts, then the probability of one driver wearing a seat belt is 0.8. So, the probability of all three drivers wearing their seat belts would be 0.8 x 0.8 x 0.8, which equals 0.512 or 51.2%. So, there you have it, buckle up and enjoy the ride!
284.1243 in word form is: two hundred eighty-four and one thousand two hundred forty-three ten-thousandths.
75 is 54 percent of eighty!!!!!!!!!!!!!!
The answer is 50%.
10 percent of eighty is 8... 2.5 percent of eight is 2.... 8 + 2 = 10.
In which was about eighty percent of the population engaged in the late 1700s?
Eighty percent.
I take it you mean 80%If so the probability of "not making 100" is 20%, 1/5 or 0.2
Yes. Fifty percent would be half of 100, and eighty-three percent is greater than fifty percent.
eighty percent
eighty percent
It's 81 percent
32
16